作业帮(3x^2y^4+(-2xy^2)^2)/(-3x^2y^3) 怎么做? 过程详细点
来源：学生作业帮助网 编辑：作业帮 时间：2024/12/01 17:34:41
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(3x^2y^4+(-2xy^2)^2)/(-3x^2y^3) 怎么做? 过程详细点
(3x^2y^4+(-2xy^2)^2)/(-3x^2y^3) 怎么做? 过程详细点
(3x^2y^4+(-2xy^2)^2)/(-3x^2y^3) 怎么做? 过程详细点
原式=(3x^2y^4+4x^2y^4)/(-3x^2y^3)
=7x^2y^4/(-3x^2y^3)
=-7y/3
(x)=2a(1-cos2x)/2-√3asin2x+a+b
=-acos2x-√3asin2x+2a+b
=-2asin(2x+π/6)+2a+b
π/6<=2x+π/6<=7π/6
所以-1/2<=sin(2x+π/6)<=1
a>0,-2a<0
则最大=-2a*(-1/2)+2a+b=3a+b=1
最小=-2a*1+2a+b=-5
a=2,b=-5
a<0,-2a>0
则最大=-2a*1+2a+b=1
最小=3a+b=-5
a=-2,b=1
a=2,b=-5
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化简：2x²y+{2xy-[3x²y-2(-3x²y+2xy)]-4xy}化简：2x²y+{2xy-[3x²y-2(-3x²y+2xy)]-4xy}
计算：5xy^2-[3xy^2-(4xy^2-2x^2y)]+2x^2y-xy^2