已知函数f(x)=2cos(kx+π/3)+b(k>0)的最小正周期为π,最小值为3(1)求k,b的值,并写出相应的f(x)解析式(2)求M(x)=F(x-π/4)+F(x)的最大值和最小值
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![已知函数f(x)=2cos(kx+π/3)+b(k>0)的最小正周期为π,最小值为3(1)求k,b的值,并写出相应的f(x)解析式(2)求M(x)=F(x-π/4)+F(x)的最大值和最小值](/uploads/image/z/8608235-59-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D2cos%28kx%2B%CF%80%2F3%29%2Bb%28k%3E0%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E4%B8%BA%CF%80%2C%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA3%EF%BC%881%EF%BC%89%E6%B1%82k%2Cb%E7%9A%84%E5%80%BC%2C%E5%B9%B6%E5%86%99%E5%87%BA%E7%9B%B8%E5%BA%94%E7%9A%84f%28x%29%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%882%EF%BC%89%E6%B1%82M%28x%29%3DF%28x-%CF%80%2F4%29%2BF%28x%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC)
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已知函数f(x)=2cos(kx+π/3)+b(k>0)的最小正周期为π,最小值为3(1)求k,b的值,并写出相应的f(x)解析式(2)求M(x)=F(x-π/4)+F(x)的最大值和最小值
已知函数f(x)=2cos(kx+π/3)+b(k>0)的最小正周期为π,最小值为3
(1)求k,b的值,并写出相应的f(x)解析式
(2)求M(x)=F(x-π/4)+F(x)的最大值和最小值
已知函数f(x)=2cos(kx+π/3)+b(k>0)的最小正周期为π,最小值为3(1)求k,b的值,并写出相应的f(x)解析式(2)求M(x)=F(x-π/4)+F(x)的最大值和最小值
已知函数f(x)=2cos(kx+π/3)+b(k>0)的最小正周期为π,最小值为3
(1)求k,b的值,并写出相应的f(x)解析式
k=2,b=5
f(x)=2cos(2x+π/3)+5
(2)求M(x)=F(x-π/4)+F(x)的最大值和最小值
M(x)=F(x-π/4)+F(x)=2cos(2(x-π/4)+π/3)+5+2cos(2x+π/3)+5
=2(cos(2x-π/2+π/3)+2cos(2x+π/3))+10
=2(sin(2x+π/3)+cos(2x+π/3))+10
=2√2sin(2x+π/3+π/4)+10
sin(2x+π/3+π/4)的最大值1,最小值-1
M(x)的最大值10+2√2,最小值10-2√2