一般多项式拟合,最小平方误差要怎么求?要源代码
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 00:22:25
![一般多项式拟合,最小平方误差要怎么求?要源代码](/uploads/image/z/8612778-66-8.jpg?t=%E4%B8%80%E8%88%AC%E5%A4%9A%E9%A1%B9%E5%BC%8F%E6%8B%9F%E5%90%88%2C%E6%9C%80%E5%B0%8F%E5%B9%B3%E6%96%B9%E8%AF%AF%E5%B7%AE%E8%A6%81%E6%80%8E%E4%B9%88%E6%B1%82%3F%E8%A6%81%E6%BA%90%E4%BB%A3%E7%A0%81)
xRJA_b^g;n
Zo=EJ=HPQYPVͨAa{=|_]|3"w!9oxa|?$<lkv=wp~~y,!g9pn;p b@JC@D Q8"iF-[|iԶRX誡6
5A>C[1 ]GF]BYdskT"r+TM b0GcH/jT|PzPɋXFWU3 ^RQB/5nkRJaШԚeӘ?dp8[)#5_[|`d2jlj+Ym
一般多项式拟合,最小平方误差要怎么求?要源代码
一般多项式拟合,最小平方误差要怎么求?要源代码
一般多项式拟合,最小平方误差要怎么求?要源代码
>>x0=[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24];
>>y0=[8.28,8.76,9.29,10.73,10.88,11.34,11.97,12.02,12.16,12.83,13.90,14.71,16.11,16.40,17.07,6.96,16.88,17.20,19.87,20.19,20.00,19.81,19.40,20.48];
>> plot(x0,y0,x0,y0,'*')
>> p2=polyfit(x0,y0,2);
>>ye=y0-polyval(p2,x0);
>> ye2s=sum(ye.^2);
>> disp(sprintf('误差的平方和=%d',ye2s));
误差的平方和=9.468029e+000
>> plot(x0,y0,x0,y0,'*',x0,polyval(p2,x0),'--')