已知x2+y2-4x-10y+29=0求x2y2+2x3y2+x4y2的值
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已知x2+y2-4x-10y+29=0求x2y2+2x3y2+x4y2的值
已知x2+y2-4x-10y+29=0求x2y2+2x3y2+x4y2的值
已知x2+y2-4x-10y+29=0求x2y2+2x3y2+x4y2的值
由x²+y²-4x-10y+29=0
得(x-2)²+(y-5)²=0
所以x=2 y=5
所以 x²y²+2x^3*y²+x^4*y²
=4*25+2*8*25+16*25
=100+400+400
=600
∵x^2+y^2-4x-10y+29=0
∴x^2-4x+4+y^2-10y+25=0(4和25是由29拆成的)
∴(x-2)^2+(y-5)^2=0
∴x-2=0 ,y-5=0
∴x=2,y=5
∴原式=(xy)^2(x+1)^2=100x9=900
愿采纳,我可是打了好长时间呢~~(*^__^*) 嘻嘻……,O(∩_∩)O谢谢