已知斜率为1的直线l与双曲线C:x^2/a^2-y^2/b^2=1相交于B、D两点,且BD的中点M(1,3),1.求C的离心率,2.设C点的右顶点为A,右焦点为F,DF的膜*BF的膜=17,证明A,B,D三点的圆与X轴相切.
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![已知斜率为1的直线l与双曲线C:x^2/a^2-y^2/b^2=1相交于B、D两点,且BD的中点M(1,3),1.求C的离心率,2.设C点的右顶点为A,右焦点为F,DF的膜*BF的膜=17,证明A,B,D三点的圆与X轴相切.](/uploads/image/z/8625374-62-4.jpg?t=%E5%B7%B2%E7%9F%A5%E6%96%9C%E7%8E%87%E4%B8%BA1%E7%9A%84%E7%9B%B4%E7%BA%BFl%E4%B8%8E%E5%8F%8C%E6%9B%B2%E7%BA%BFC%EF%BC%9Ax%5E2%2Fa%5E2-y%5E2%2Fb%5E2%3D1%E7%9B%B8%E4%BA%A4%E4%BA%8EB%E3%80%81D%E4%B8%A4%E7%82%B9%2C%E4%B8%94BD%E7%9A%84%E4%B8%AD%E7%82%B9M%EF%BC%881%2C3%EF%BC%89%2C1.%E6%B1%82C%E7%9A%84%E7%A6%BB%E5%BF%83%E7%8E%87%2C2.%E8%AE%BEC%E7%82%B9%E7%9A%84%E5%8F%B3%E9%A1%B6%E7%82%B9%E4%B8%BAA%2C%E5%8F%B3%E7%84%A6%E7%82%B9%E4%B8%BAF%2CDF%E7%9A%84%E8%86%9C%2ABF%E7%9A%84%E8%86%9C%3D17%2C%E8%AF%81%E6%98%8EA%2CB%2CD%E4%B8%89%E7%82%B9%E7%9A%84%E5%9C%86%E4%B8%8EX%E8%BD%B4%E7%9B%B8%E5%88%87.)
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已知斜率为1的直线l与双曲线C:x^2/a^2-y^2/b^2=1相交于B、D两点,且BD的中点M(1,3),1.求C的离心率,2.设C点的右顶点为A,右焦点为F,DF的膜*BF的膜=17,证明A,B,D三点的圆与X轴相切.
已知斜率为1的直线l与双曲线C:x^2/a^2-y^2/b^2=1相交于B、D两点,且BD的中点M(1,3),1.求C的离心率,
2.设C点的右顶点为A,右焦点为F,DF的膜*BF的膜=17,证明A,B,D三点的圆与X轴相切.
已知斜率为1的直线l与双曲线C:x^2/a^2-y^2/b^2=1相交于B、D两点,且BD的中点M(1,3),1.求C的离心率,2.设C点的右顶点为A,右焦点为F,DF的膜*BF的膜=17,证明A,B,D三点的圆与X轴相切.
二级了,直接上图