已知f(x)=log3(x+6),若(m+6)(n+6)=27,则f[f(m)+f(n)]的值.\(≥▽≤)/~
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 17:04:41
![已知f(x)=log3(x+6),若(m+6)(n+6)=27,则f[f(m)+f(n)]的值.\(≥▽≤)/~](/uploads/image/z/8629617-57-7.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%29%3Dlog3%28x%2B6%29%2C%E8%8B%A5%EF%BC%88m%2B6%EF%BC%89%EF%BC%88n%2B6%EF%BC%89%3D27%2C%E5%88%99f%5Bf%28m%29%2Bf%28n%29%5D%E7%9A%84%E5%80%BC.%5C%28%E2%89%A5%E2%96%BD%E2%89%A4%29%2F%7E)
x){}K4*4msӍ5*4u^t/}#WN #̰52y13-:M#WS;M#O3
{b4u.}4m%u6IET1lv64s4\
TQ`,X4X̏(2263ִ5#,ئikBXm@qFP~qAb6`^"9cL\Iu
已知f(x)=log3(x+6),若(m+6)(n+6)=27,则f[f(m)+f(n)]的值.\(≥▽≤)/~
已知f(x)=log3(x+6),若(m+6)(n+6)=27,则f[f(m)+f(n)]的值.
\(≥▽≤)/~
已知f(x)=log3(x+6),若(m+6)(n+6)=27,则f[f(m)+f(n)]的值.\(≥▽≤)/~
f(m)+f(n)=log3(m+6)+log3(n+6)=log3[(m+6)(n+6)]=log3(27)=log3(3^3)=3
所以
f[f(m)+f(n)]
=f(3)
=log3(3+6)
=log3(3^2)
=2
f(m)+f(n)=log3(m+6)+log3(n+6)
=log3(m+6)(n+6)
=log3 27
=3
f[f(m)+f(n)]
=f(3)
=log3 (3+6)
=2
2
2