作业帮求{根号下[(1-cosx)\(1+cosx)]}+{根号下[(1+cosx)\(1-cosx) ]} ,x为第四象限角
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![求{根号下[(1-cosx)\(1+cosx)]}+{根号下[(1+cosx)\(1-cosx) ]} ,x为第四象限角](/uploads/image/z/8629678-46-8.jpg?t=%E6%B1%82%7B%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%281-cosx%29%5C%281%2Bcosx%29%5D%7D%2B%7B%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%281%2Bcosx%29%5C%281-cosx%29+%5D%7D+%2Cx%E4%B8%BA%E7%AC%AC%E5%9B%9B%E8%B1%A1%E9%99%90%E8%A7%92)
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求{根号下[(1-cosx)\(1+cosx)]}+{根号下[(1+cosx)\(1-cosx) ]} ,x为第四象限角
求{根号下[(1-cosx)\(1+cosx)]}+{根号下[(1+cosx)\(1-cosx) ]} ,x为第四象限角
求{根号下[(1-cosx)\(1+cosx)]}+{根号下[(1+cosx)\(1-cosx) ]} ,x为第四象限角
x为第四象限角,
所以cosx>0,sinx