1\a+1/b=5 求3a+ab+3b\a-2ab+b的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/12 07:06:38
![1\a+1/b=5 求3a+ab+3b\a-2ab+b的值](/uploads/image/z/8634006-54-6.jpg?t=1%5Ca%2B1%2Fb%3D5+%E6%B1%823a%2Bab%2B3b%5Ca-2ab%2Bb%E7%9A%84%E5%80%BC)
x
@Wp 8%%
{ QQ@!8I(YOРt~zϟMJQsjHRS>MihrPdfxc}T()5g:HNUks!Sǵ.WŃ5" tS hY6N0=x}/¥ovA+;o!
1\a+1/b=5 求3a+ab+3b\a-2ab+b的值
1\a+1/b=5 求3a+ab+3b\a-2ab+b的值
1\a+1/b=5 求3a+ab+3b\a-2ab+b的值
因为1/a+1/b=(a+b)/ab=5
(a+b)=5ab
代数式=(3(a+b)+ab)/((a+b)-2ab
=(3*5ab+ab)/(5ab-2ab)
=16ab/3ab
=16/3
1/a+1/b=5
(a+b)/ab=5
a+b=5ab,
(3a+ab+3b)/(a-2ab+b)
=[3(a+b)+ab]/(a+b-2ab)
=(15ab+ab)/(5ab-2ab)
=16ab/(3ab)
=16/3