作业帮设函数f(x)连续 (1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)设函数f(x)连续(1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)]dx
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![设函数f(x)连续 (1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)设函数f(x)连续(1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)]dx](/uploads/image/z/8641947-3-7.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%E8%BF%9E%E7%BB%AD+%281%29%E8%AF%81%E6%98%8E%EF%BC%9A%E2%88%AB%E4%B8%8Aa%E4%B8%8B-af%28x%29dx%3D1%2F2%E2%88%AB%E4%B8%8Aa%E4%B8%8B-a%5Bf%28x%29%2Bf%28-x%29%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%E8%BF%9E%E7%BB%AD%281%29%E8%AF%81%E6%98%8E%EF%BC%9A%E2%88%AB%E4%B8%8Aa%E4%B8%8B-af%28x%29dx%3D1%2F2%E2%88%AB%E4%B8%8Aa%E4%B8%8B-a%5Bf%28x%29%2Bf%28-x%29%5Ddx)
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设函数f(x)连续 (1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)设函数f(x)连续(1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)]dx
设函数f(x)连续 (1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)
设函数f(x)连续
(1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)]dx
设函数f(x)连续 (1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)设函数f(x)连续(1)证明：∫上a下-af(x)dx=1/2∫上a下-a[f(x)+f(-x)]dx
题目都给了这么大提示了还不愿做,懒的可以