作业帮若定义一种新的运算为a*b=ab/(1-ab),计算[（3*2)]*6分之13*2即a=3,b=2所以3*2=(3×2)/(1-3×2(=-6/5所以(3*2)*1/6=(-6/5)*(1/6)=(-6/5×1/6)/[1-(-6/5×1/6)] =(-1/5)/((6/5)=-1/6
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/18 21:44:13
![若定义一种新的运算为a*b=ab/(1-ab),计算[（3*2)]*6分之13*2即a=3,b=2所以3*2=(3×2)/(1-3×2(=-6/5所以(3*2)*1/6=(-6/5)*(1/6)=(-6/5×1/6)/[1-(-6/5×1/6)] =(-1/5)/((6/5)=-1/6](/uploads/image/z/86425-25-5.jpg?t=%E8%8B%A5%E5%AE%9A%E4%B9%89%E4%B8%80%E7%A7%8D%E6%96%B0%E7%9A%84%E8%BF%90%E7%AE%97%E4%B8%BAa%2Ab%3Dab%2F%281-ab%29%2C%E8%AE%A1%E7%AE%97%5B%EF%BC%883%2A2%29%5D%2A6%E5%88%86%E4%B9%8B13%2A2%E5%8D%B3a%3D3%2Cb%3D2%E6%89%80%E4%BB%A53%2A2%3D%283%C3%972%29%2F%281-3%C3%972%28%3D-6%2F5%E6%89%80%E4%BB%A5%283%2A2%29%2A1%2F6%3D%28-6%2F5%29%2A%281%2F6%29%3D%28-6%2F5%C3%971%2F6%29%2F%5B1-%28-6%2F5%C3%971%2F6%29%5D+%3D%28-1%2F5%29%2F%28%286%2F5%29%3D-1%2F6)
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若定义一种新的运算为a*b=ab/(1-ab),计算[（3*2)]*6分之13*2即a=3,b=2所以3*2=(3×2)/(1-3×2(=-6/5所以(3*2)*1/6=(-6/5)*(1/6)=(-6/5×1/6)/[1-(-6/5×1/6)] =(-1/5)/((6/5)=-1/6
若定义一种新的运算为a*b=ab/(1-ab),计算[（3*2)]*6分之1
3*2即a=3,b=2
所以3*2=(3×2)/(1-3×2(=-6/5
所以(3*2)*1/6=(-6/5)*(1/6)
=(-6/5×1/6)/[1-(-6/5×1/6)]
=(-1/5)/((6/5)
=-1/6
若定义一种新的运算为a*b=ab/(1-ab),计算[（3*2)]*6分之13*2即a=3,b=2所以3*2=(3×2)/(1-3×2(=-6/5所以(3*2)*1/6=(-6/5)*(1/6)=(-6/5×1/6)/[1-(-6/5×1/6)] =(-1/5)/((6/5)=-1/6
将-6/5看成a,最后面的1/6看成b
意思是先计算出3*2=-6/5
然后把3*2=-6/5代入式子中去。
将-6/5看作a，将1/6看作b