If sin(x) = 4/5,pi/2 < x < pi,find the value of sin(2x)

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If sin(x) = 4/5,pi/2 < x < pi,find the value of sin(2x)
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If sin(x) = 4/5,pi/2 < x < pi,find the value of sin(2x)
If sin(x) = 4/5,pi/2 < x < pi,find the value of sin(2x)

If sin(x) = 4/5,pi/2 < x < pi,find the value of sin(2x)
sin2x=2sinxcosx
∵sinx=4/5
∵π/2∵(sinx)^2+(cosx)^2=1
∴cosx=-3/5
∴sin2x=2sinxcosx=-24/25

sin(x) = 4/5, pi/2 < x < pi
cosx=(1-sin^2x)^(1/2)=-3/5
sin(2x)=2sinxcosx=2*4/5*(-3/5)=-24/25