已知a b c 为不等式零的实数,且a+b+c=0,求a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)的值分解因式:(X^4+4x^2+1)(x^4+3x^2+1)+10x^4 还有一题哦!
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![已知a b c 为不等式零的实数,且a+b+c=0,求a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)的值分解因式:(X^4+4x^2+1)(x^4+3x^2+1)+10x^4 还有一题哦!](/uploads/image/z/8652551-23-1.jpg?t=%E5%B7%B2%E7%9F%A5a+b+c+%E4%B8%BA%E4%B8%8D%E7%AD%89%E5%BC%8F%E9%9B%B6%E7%9A%84%E5%AE%9E%E6%95%B0%2C%E4%B8%94a%2Bb%2Bc%3D0%2C%E6%B1%82a%281%2Fb%2B1%2Fc%29%2Bb%281%2Fc%2B1%2Fa%29%2Bc%281%2Fa%2B1%2Fb%29%E7%9A%84%E5%80%BC%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%9A%EF%BC%88X%5E4%2B4x%5E2%2B1%29%28x%5E4%2B3x%5E2%2B1%29%2B10x%5E4+%E8%BF%98%E6%9C%89%E4%B8%80%E9%A2%98%E5%93%A6%EF%BC%81)
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已知a b c 为不等式零的实数,且a+b+c=0,求a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)的值分解因式:(X^4+4x^2+1)(x^4+3x^2+1)+10x^4 还有一题哦!
已知a b c 为不等式零的实数,且a+b+c=0,求a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)的值
分解因式:(X^4+4x^2+1)(x^4+3x^2+1)+10x^4
还有一题哦!
已知a b c 为不等式零的实数,且a+b+c=0,求a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)的值分解因式:(X^4+4x^2+1)(x^4+3x^2+1)+10x^4 还有一题哦!
原式=a(1/b+1/c+1/a)+b(1/c+1/a+1/b)+c(1/a+1/b+1/c)-3
=(a+b+c)(1/a+1/b+1/c)-3
=0-3
=-3
-3
原式=(a+b)/c+(b+c)/a+(a+c)/b=-c/c-a/a-b/b=-3