x^2-4xy+4y^2 =0,n那么(x^2 -2xy+3y)分之(x-y)等于?

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x^2-4xy+4y^2 =0,n那么(x^2 -2xy+3y)分之(x-y)等于?
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x^2-4xy+4y^2 =0,n那么(x^2 -2xy+3y)分之(x-y)等于?
x^2-4xy+4y^2 =0,n那么(x^2 -2xy+3y)分之(x-y)等于?

x^2-4xy+4y^2 =0,n那么(x^2 -2xy+3y)分之(x-y)等于?
X^2-4xy+4y^2=0
这是个完全平方啊
可化简为(X-2Y)^2=0
根据平方的非负性可以推出X=2Y
所以说将X=2Y代入到(x-y)/(x^2 -2xy+3y)=(2y-y)/(4y^2-4y^2+3y)=1/3
楼上算错了