直角三角形ABC中,角C=96.P为三角形ABC所在平面外一点,PA垂直平面ABC,且AE垂直PB,AF垂直PC,E,F为垂足,求证:1.AF垂直平面PBC2.PB垂直平面AEF
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![直角三角形ABC中,角C=96.P为三角形ABC所在平面外一点,PA垂直平面ABC,且AE垂直PB,AF垂直PC,E,F为垂足,求证:1.AF垂直平面PBC2.PB垂直平面AEF](/uploads/image/z/8653095-63-5.jpg?t=%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92C%3D96.P%E4%B8%BA%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E6%89%80%E5%9C%A8%E5%B9%B3%E9%9D%A2%E5%A4%96%E4%B8%80%E7%82%B9%2CPA%E5%9E%82%E7%9B%B4%E5%B9%B3%E9%9D%A2ABC%2C%E4%B8%94AE%E5%9E%82%E7%9B%B4PB%2CAF%E5%9E%82%E7%9B%B4PC%2CE%2CF%E4%B8%BA%E5%9E%82%E8%B6%B3%2C%E6%B1%82%E8%AF%81%EF%BC%9A1.AF%E5%9E%82%E7%9B%B4%E5%B9%B3%E9%9D%A2PBC2.PB%E5%9E%82%E7%9B%B4%E5%B9%B3%E9%9D%A2AEF)
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