计算log4(3)*log9(32)

计算log4(3)*log9(32) 对数函数计算 log4 3·log9 2-log1/2 4次根号32 计算log9(根号2)*[log4(3)+log8(3)] 计算:(log4 3+log8 3)×log9 √2=? 计算:(1/4)^log4^1/3-lg25-lg4-log9^27 log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(27)+log9(2)*log4(根27) log9×log4 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32 计算（log4 3+ log8 3）（log3 2+ log9 2）-- log1/2 32^(1/3)+5^（log259） (log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32) 1把loga^b表示成以b为底的对数2把loga^nb^n表示成以a为底的对数计算 log4^32 log9^8 * lg32^27log4^27/log4^3 (log4^3+log8^3)(log3^2+log9^2) 计算:log27(32)×log64(27)+log9(2)×log4(√27)= (log4^3+log8^3)(log3^2+log9^2)详细计算过程.~ 各位大神log4(3)log9(2)-log1/2(4√32)怎做啊?是不是？ 计算3^log9(64) (log3^2 + log9^4)×(log4^3 + log8^3) (log3 2+log9 2)*(log4 3+log8 3)求值 化简(log4(3)+log8(3))(log3(2)+log9(2))