已知:4a²+b²+4a-12b+37=0 求√a²-2ab的值如题
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已知:4a²+b²+4a-12b+37=0 求√a²-2ab的值如题
已知:4a²+b²+4a-12b+37=0 求√a²-2ab的值
如题
已知:4a²+b²+4a-12b+37=0 求√a²-2ab的值如题
4a²+b²+4a-12b+37=0
4a²+4a+1+b²-12b+36=0
(2a+1)²+(b-6)²=0
2a+1=0 a=-1/2
b-6=0 b=6
√(a²-2ab)=√[(1/4)-2(-1/2)6]=√(25/4)=5/2
4a²+b²+4a-12b+37=0, 分解得出4a²+4a+1+b²-12b+36=0,所以(2a+1)²+(b-6)²=0,所以 a=-1/2,b=6;
√a²-2ab=√1/4+2*1/2*6=根号25除以2