已知x,y为正整数,且x²-y²=5,求x,y的值
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已知x,y为正整数,且x²-y²=5,求x,y的值
已知x,y为正整数,且x²-y²=5,求x,y的值
已知x,y为正整数,且x²-y²=5,求x,y的值
首先,分析题目:这是平方差:
x^2-y^2=(x+y)(x-y)
=5=5*1 所以X+Y=5①,X-Y=1②
将②化简:X=1+Y③,将③带入①得:1+Y+Y=5,2Y=4,所以Y=2
将Y=2代入①X+2=5,所以X=3.
x^2-y^2
=(x+y)(x-y)=5=5*1
x+y=5
x-y=1
x=3
y=2