X+y+z=26,x-y=1,2x-y+z=18
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X+y+z=26,x-y=1,2x-y+z=18
X+y+z=26,x-y=1,2x-y+z=18
X+y+z=26,x-y=1,2x-y+z=18
1式和2式相加 2X+Z=27
1式和3式相加 3X+2Z=44
这是个二元一次 用带入消元法 将Z=27-2X 代入第二个
得X=10所以其他
Y=9
Z=7
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
X+y+z=26,x-y=1,2x-y+z=18
(x+y-z)(x-y+z)=
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1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
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x+y+z=6 x+2y+3z=14 y+1=z
X+2Y= -12X+Y+Z= 1-X+Y-Z= -1
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
计算题!【x+y+z=26;x-y=1;2x-y+z=18】!【x/3+y/5;x/2-2y/5=1】