作业帮[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/29 23:18:51
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[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
(x^2-4y^2)(x+y)=(x+2y)(x-2y)（x+y）
(x^2+xy-2y^2)=(x+2y)(x-y)
x^2-y^2=(x+y)(x-y)
先计算分母部分=(x+2y)/(x+y)
原式=[(x+2y)(x-2y)(x+y)]/[(x+2y)/(x+y)]
=(x-2y)(x+y)^2