已知tan(3π/2+θ)等于根号3,求cos(θ+7π/2)的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 06:33:05
x){}KK47i~OOv=[ivcg56)jyڰ&H"v6 YF -D飨}1XEXH5eCsk6PV }Af{
&tΊ';|q˙Mm9C
l@a
已知tan(3π/2+θ)等于根号3,求cos(θ+7π/2)的值
已知tan(3π/2+θ)等于根号3,求cos(θ+7π/2)的值
已知tan(3π/2+θ)等于根号3,求cos(θ+7π/2)的值
cos(θ+7π/2)=cos(θ+3π/2)
tan(θ+3π/2)=sin(θ+3π/2)/cos(θ+3π/2)=√3 sin(θ+3π/2)=√3cos(θ+3π/2)
sin²(θ+3π/2)+cos²(θ+3π/2)=1 -->cos²(θ+3π/2)=1/4
显然θ+3π/2在一三象限 故cos(θ+7π/2)=cos(θ+3π/2)=±1/2