已知cos(α+β)=0,求证tan(2α+β)=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/03 06:34:56
![已知cos(α+β)=0,求证tan(2α+β)=0](/uploads/image/z/8701464-48-4.jpg?t=%E5%B7%B2%E7%9F%A5cos%28%CE%B1%2B%CE%B2%29%3D0%2C%E6%B1%82%E8%AF%81tan%282%CE%B1%2B%CE%B2%29%3D0)
x){}K5m>I@ƦK4`b6IE*/!ܗf2ɮ6'.k:|ιM LiLzH$֎d RECU 6XYƏ: [\gr3 ~|u
已知cos(α+β)=0,求证tan(2α+β)=0
已知cos(α+β)=0,求证tan(2α+β)=0
已知cos(α+β)=0,求证tan(2α+β)=0
题错了,例如α=π/3,β=π/6,则α+β=π/2,2α+β=5π/6
cos(α+β)=cos(π/2)=0,而tan(2α+β)=tan(5π/6)=-√3/3≠0