(n^2+1)^2+4n(n^2+1)+4n^2
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(n^2+1)^2+4n(n^2+1)+4n^2
(n^2+1)^2+4n(n^2+1)+4n^2
(n^2+1)^2+4n(n^2+1)+4n^2
(n^2+1)^2+4n(n^2+1)+4n^2
=(n^2+1)^2+2(2n)(n^2+1)+(2n)^2
=(n^2+1+2n)^2
=(n+1)^4
(n²+1)²+4n(n²+1)+4n²= [(n²+1)+2n ] ² =(n²+2n+1)²=[ (n+1)² ]²=(n+1)的四次方