已知函数f(x)的定义域为【0,1】,且同时满足:①f(x)=-3,②f(1)≤1恒成立;③,若x1≥0,x2≥0,x1+x2≤1则有f(x1+x2)≤F(x1)+f(x2)-1,试求:(1)f(0)的值,(2)函数f(x)的值!(2)是求f(x)的最值,①是f(1)=-3,③是
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![已知函数f(x)的定义域为【0,1】,且同时满足:①f(x)=-3,②f(1)≤1恒成立;③,若x1≥0,x2≥0,x1+x2≤1则有f(x1+x2)≤F(x1)+f(x2)-1,试求:(1)f(0)的值,(2)函数f(x)的值!(2)是求f(x)的最值,①是f(1)=-3,③是](/uploads/image/z/8709300-36-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%E3%80%900%2C1%E3%80%91%2C%E4%B8%94%E5%90%8C%E6%97%B6%E6%BB%A1%E8%B6%B3%EF%BC%9A%E2%91%A0f%28x%29%3D-3%2C%E2%91%A1f%281%29%E2%89%A41%E6%81%92%E6%88%90%E7%AB%8B%EF%BC%9B%E2%91%A2%2C%E8%8B%A5x1%E2%89%A50%2Cx2%E2%89%A50%2Cx1%2Bx2%E2%89%A41%E5%88%99%E6%9C%89f%28x1%2Bx2%29%E2%89%A4F%28x1%29%2Bf%28x2%29-1%2C%E8%AF%95%E6%B1%82%EF%BC%9A%EF%BC%881%EF%BC%89f%280%29%E7%9A%84%E5%80%BC%2C%EF%BC%882%EF%BC%89%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%80%BC%21%282%29%E6%98%AF%E6%B1%82f%28x%29%E7%9A%84%E6%9C%80%E5%80%BC%EF%BC%8C%E2%91%A0%E6%98%AFf%281%29%3D-3%2C%E2%91%A2%E6%98%AF)
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已知函数f(x)的定义域为【0,1】,且同时满足:①f(x)=-3,②f(1)≤1恒成立;③,若x1≥0,x2≥0,x1+x2≤1则有f(x1+x2)≤F(x1)+f(x2)-1,试求:(1)f(0)的值,(2)函数f(x)的值!(2)是求f(x)的最值,①是f(1)=-3,③是
已知函数f(x)的定义域为【0,1】,且同时满足:①f(x)=-3,②f(1)≤1恒成立;③,若x1≥0,x2≥0,x1+x2≤1
则有f(x1+x2)≤F(x1)+f(x2)-1,试求:
(1)f(0)的值,(2)函数f(x)的值!
(2)是求f(x)的最值,①是f(1)=-3,③是f(x)≤1恒成立
已知函数f(x)的定义域为【0,1】,且同时满足:①f(x)=-3,②f(1)≤1恒成立;③,若x1≥0,x2≥0,x1+x2≤1则有f(x1+x2)≤F(x1)+f(x2)-1,试求:(1)f(0)的值,(2)函数f(x)的值!(2)是求f(x)的最值,①是f(1)=-3,③是
①f(x)=-3 你确定这个条件没错?
no