已知函数f(x)=Asin(2x+π/3)且图像经过点(π/4,1) 求若α∈(π/2,π),f[(3α-π)/6]=2/3,求tan2α的值,
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 23:55:01
![已知函数f(x)=Asin(2x+π/3)且图像经过点(π/4,1) 求若α∈(π/2,π),f[(3α-π)/6]=2/3,求tan2α的值,](/uploads/image/z/8710870-22-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3DAsin%EF%BC%882x%2B%CF%80%2F3%EF%BC%89%E4%B8%94%E5%9B%BE%E5%83%8F%E7%BB%8F%E8%BF%87%E7%82%B9%EF%BC%88%CF%80%2F4%2C1%EF%BC%89+%E6%B1%82%E8%8B%A5%CE%B1%E2%88%88%EF%BC%88%CF%80%2F2%2C%CF%80%EF%BC%89%2Cf%EF%BC%BB%EF%BC%883%CE%B1-%CF%80%EF%BC%89%2F6%EF%BC%BD%3D2%2F3%2C%E6%B1%82tan2%CE%B1%E7%9A%84%E5%80%BC%2C)
x͒JP_1 .C `:4EKK\*I=}|lyϽu95]+{y*¬3UKwchm|bxgWĽS#Ruy.4ATb]%c
Pv e'yxF#Z?;Pp_̈KۦCTopfxt ЧCJNMKkKbG_!KN.}8|I*p_bS
HXW!a` BlcdO@b| PpHbkVh:gd$k;eע
已知函数f(x)=Asin(2x+π/3)且图像经过点(π/4,1) 求若α∈(π/2,π),f[(3α-π)/6]=2/3,求tan2α的值,
已知函数f(x)=Asin(2x+π/3)且图像经过点(π/4,1) 求
若α∈(π/2,π),f[(3α-π)/6]=2/3,求tan2α的值,
已知函数f(x)=Asin(2x+π/3)且图像经过点(π/4,1) 求若α∈(π/2,π),f[(3α-π)/6]=2/3,求tan2α的值,
解由函数f(x)=Asin(2x+π/3)且图像经过点(π/4,1)
即Asin(2×π/4+π/3)=1
即Asin(π/2+π/3)=1
即Acos(π/3)=1
即A×1/2=1
即A=2
故f(x)=2sin(2x+π/3)
f[(3α-π)/6]=2/3=2sin(2*(3α-π)/6+π/3)=2sina
所以sina=1/3
α∈(π/2,π)2α∈(π,2π)cosa=-2√2
tan2α
=sin2a/cos2a
=2sinacosa/[1-2(sina)^2]
=2*(1/3)*(-2√2)/[1-2*(1/3)^2]
=-12√2/7
已知函数f(x)=Asin(2x+φ),当x=-π/3时,最小值为-4,
已知函数f(x)=Asin
已知函数f(x)=Asin(2wx+π/3)+m(A>0,w
已知函数f(x)=Asin(2wx+π/3)+m(A>0,w
已知函数 f(x)=Asin(π/3x+b),x∈R,A>0,0
已知函数f(x)是奇函数,当x<0时,fx)=x-2asin(πx/2),若f(3)=6,则a是什么
已知a>0,函数f(x)=-2asin(2x+ π 6已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5
已知函数f(x)=Asin(ωx+a)(A>0,ω>0,-π/2
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,-π/2
已知函数f(x)=更号2asin(x-π/4)+a+b 当a
已知函数f(x)=Asin(2x+θ),其中A≠0.
已知函数f(x)=Asin(2x+φ)(A>0,0
已知函数f(x)=asinωx·cosωx-(根号3)a(cosωx)^2+(根号3)(a+b)/2 (a>0)已知函数f(x)=asinωx·cosωx-(根号3)a(cosωx)^2+(根号3)(a+b)/2 (a>0)(1)当a=ω=1时,写出函数f(x)的单调递减区间(2)若函数f(x)满足f(x+π)=f(x),
已知函数f(x)=Asin(x+&)(A>0,0
已知函数f[x]=Asin²【ωx+
已知函数f(x)=Asin(x+q) (0
已知函数f(x)=Asin(ωx+φ)
已知函数f(x)=Asin(2x+a),若函数f(x+π/6)为偶函数,且f(π/6)=4,求f(x)解析式