A={x|x²-2x-8=0}B={x|x²+2(a-1)x+a²-8=0},A∪B=A,a取值集合
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A={x|x²-2x-8=0}B={x|x²+2(a-1)x+a²-8=0},A∪B=A,a取值集合
A={x|x²-2x-8=0}B={x|x²+2(a-1)x+a²-8=0},A∪B=A,a取值集合
A={x|x²-2x-8=0}B={x|x²+2(a-1)x+a²-8=0},A∪B=A,a取值集合
x²-2x-8=0
解得
x=4
x=-2
易知
A={-2,4}
A∪B=A
B可以空集,或者{-2}或{4}或{-2,4}
为空集时
(2(a-1))^2-4(a^2-8)9/2