求导y=arctan√(x^2-1)-(lnx/√(x^2-1))

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/25 21:13:26
求导y=arctan√(x^2-1)-(lnx/√(x^2-1))
xRr0M66ZK*q6Бd6°a7w ?o,{=wn{y1 3g1\ l(NK3%c_ᘾAwhM9Lhǩ v!`¾YS/RXIJ:6/d?M聙o'nhUH;7X{waGlL<=%=ܿ@6'/*T%,h S\#ULĕ'd%Eoj.xr{_"[";#oAU\oťϴǘYD)XpNXII +G2Ra!BW!~D@uR9P(jT DY\ƒ`3&I0XY]&T?Q

求导y=arctan√(x^2-1)-(lnx/√(x^2-1))
求导y=arctan√(x^2-1)-(lnx/√(x^2-1))

求导y=arctan√(x^2-1)-(lnx/√(x^2-1))
(arctanx)' = 1/(x² + 1)
(lnx)' = 1/x
(u/v)' = (u'v - uv')/v²
y' = [arctan√(x² - 1)]' - [lnx/√(x² - 1)]'
= [1/(x² - 1 + 1)][√(x² - 1)]' - {(1/x)√(x² - 1) - (lnx)[√(x² - 1)]'}/(x² - 1)
= (1/2)*2x/[x²√(x² - 1)] - {[√(x² - 1)/x] - (lnx)(1/2)(2x)/√(x² - 1)}/(x² - 1)
= 1/[x√(x² - 1)] - [√(x² - 1)/x]- (xlnx)/√(x² - 1)]/(x² - 1)
= 1/[x√(x² - 1)] - 1/[x√(x² - 1)] + xlnx/[(x² - 1)√(x² - 1)]
= xlnx/[(x² - 1)√(x² - 1)]

y=arctan√x求导 求导y=arctan[2x/(1-x^2)] 急等 求导 Y=ARCTAN x/1+x^2 y=arctan(1/x)求导 y=arctan（x/2）求导? 求导 y=(arctan x)^2 求导y=arctan√(x^2-1)-(lnx/√(x^2-1)) 函数求导.y=arctan(x+1)/(x-1) 求导y=arctan(根号(1-3x))如 题、 ln(x^2+y^2)=arctan(y/x) 求导隐函数求导 arctan(1/x)求导 求导y=arctan(1-x^2) 要过程如题 arctan根号（x^2-1)求导, 方程arctan(y/x)=ln√(x²+y²)两边对x求导 y=xarcsin根号下x/(1+x)+arctan根号下x-根号2-根号x求导 求导：y=arctan(lnx) y=arctan(lnx)求导~ 隐函数求导 x=y+arctan y