-2(b-y)²-(y-x)³=
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-2(b-y)²-(y-x)³=
-2(b-y)²-(y-x)³=
-2(b-y)²-(y-x)³=
你是要展开式吗?
原式=-2(b²-2by+y²)-(y³-3xy²+3x²y-x³)
=-y³+(3x-2)y²+(4b-3x²)y+x³-2b²