(x+y)²-(x³+y³)÷(x+y)
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(x+y)²-(x³+y³)÷(x+y)
(x+y)²-(x³+y³)÷(x+y)
(x+y)²-(x³+y³)÷(x+y)
(x+y)²-(x³+y³)÷(x+y)
x^3+y^3=(x+y)(x^2-xy+y^2)
则原式变为
(x+y)²-(x^2-xy+y^2)
=(x^2+2xy+y^2)-(x^2-xy+y^2)
=3xy