作业帮设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/05 22:54:27
x){nmO't8ھ;B_BXSHB̳5qT$Vj8M"}5Ph7r;[[;^Bb^F1Ua`_\gyi9f=W!ٌO.}: I) t
设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)
设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)
设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)
x/(x+3)(2-x)>=0 =>
1.x>0 and (x>-3 and x0
没看明白 b是啥啊