作业帮数学卷22：函数f(x)=sin2ωx-2sin²ωx(ω>0)(1)若函数f(x)的周期为π,求ω的值；（2）若函数f(x)在区间[-π/16,π/16]上为增函数,求满足条件的整数ω的值.
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/20 16:38:24
![数学卷22：函数f(x)=sin2ωx-2sin²ωx(ω>0)(1)若函数f(x)的周期为π,求ω的值；（2）若函数f(x)在区间[-π/16,π/16]上为增函数,求满足条件的整数ω的值.](/uploads/image/z/8762379-51-9.jpg?t=%E6%95%B0%E5%AD%A6%E5%8D%B722%EF%BC%9A%E5%87%BD%E6%95%B0f%28x%29%3Dsin2%CF%89x-2sin%26%23178%3B%CF%89x%28%CF%89%3E0%29%281%29%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%91%A8%E6%9C%9F%E4%B8%BA%CF%80%2C%E6%B1%82%CF%89%E7%9A%84%E5%80%BC%EF%BC%9B%EF%BC%882%EF%BC%89%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%5B-%CF%80%2F16%2C%CF%80%2F16%5D%E4%B8%8A%E4%B8%BA%E5%A2%9E%E5%87%BD%E6%95%B0%2C%E6%B1%82%E6%BB%A1%E8%B6%B3%E6%9D%A1%E4%BB%B6%E7%9A%84%E6%95%B4%E6%95%B0%CF%89%E7%9A%84%E5%80%BC.)
x){6uӵ˞n72zg@4
M<F@5q@SPERZN\l';voy|'Ha= ܉O{v%Z|} hE *A=۽Ŷ.|{gS %`$`[h
;\ VSmDU:9IQ,r
Б&PLojjm\ \H*`gp4Nӟ^
#mlIyv g
数学卷22：函数f(x)=sin2ωx-2sin²ωx(ω>0)(1)若函数f(x)的周期为π,求ω的值；（2）若函数f(x)在区间[-π/16,π/16]上为增函数,求满足条件的整数ω的值.
数学卷22：函数f(x)=sin2ωx-2sin²ωx(ω>0)(1)若函数f(x)的周期为π,求ω的值；
（2）若函数f(x)在区间[-π/16,π/16]上为增函数,求满足条件的整数ω的值.
数学卷22：函数f(x)=sin2ωx-2sin²ωx(ω>0)(1)若函数f(x)的周期为π,求ω的值；（2）若函数f(x)在区间[-π/16,π/16]上为增函数,求满足条件的整数ω的值.
f(x)=sin2ωx-2sin²ωx(ω>0)
=sin2ωx+1-2sin²ωx-1
=sin2ωx+cos2ωx-1
=√2sin(2ωx+π/4)-1
f(x)的周期为π
2π/2ω=π
ω=1
(2)
ω>0
f(x)=√2sin(2ωx+π/4)-1
令-π/2+2kπ