AD,BE,CF是三角形ABC的三条高,证明AD,BE,CF必定相交于一点,即垂心提示:过A,B,C分别做对边的平行线,说明三条高所在的直线是新三角形三边上的垂直平分线我的等级图传不上来原题在九年级下册
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![AD,BE,CF是三角形ABC的三条高,证明AD,BE,CF必定相交于一点,即垂心提示:过A,B,C分别做对边的平行线,说明三条高所在的直线是新三角形三边上的垂直平分线我的等级图传不上来原题在九年级下册](/uploads/image/z/8765781-69-1.jpg?t=AD%2CBE%2CCF%E6%98%AF%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E4%B8%89%E6%9D%A1%E9%AB%98%2C%E8%AF%81%E6%98%8EAD%2CBE%2CCF%E5%BF%85%E5%AE%9A%E7%9B%B8%E4%BA%A4%E4%BA%8E%E4%B8%80%E7%82%B9%2C%E5%8D%B3%E5%9E%82%E5%BF%83%E6%8F%90%E7%A4%BA%EF%BC%9A%E8%BF%87A%2CB%2CC%E5%88%86%E5%88%AB%E5%81%9A%E5%AF%B9%E8%BE%B9%E7%9A%84%E5%B9%B3%E8%A1%8C%E7%BA%BF%2C%E8%AF%B4%E6%98%8E%E4%B8%89%E6%9D%A1%E9%AB%98%E6%89%80%E5%9C%A8%E7%9A%84%E7%9B%B4%E7%BA%BF%E6%98%AF%E6%96%B0%E4%B8%89%E8%A7%92%E5%BD%A2%E4%B8%89%E8%BE%B9%E4%B8%8A%E7%9A%84%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86%E7%BA%BF%E6%88%91%E7%9A%84%E7%AD%89%E7%BA%A7%E5%9B%BE%E4%BC%A0%E4%B8%8D%E4%B8%8A%E6%9D%A5%E5%8E%9F%E9%A2%98%E5%9C%A8%E4%B9%9D%E5%B9%B4%E7%BA%A7%E4%B8%8B%E5%86%8C)
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