Ctex这个公式怎么换行.换三行\begin{equation}\left|\frac{f(x)+f(a+b-x)}{2}-\left(x-\frac{3a+b}{4}\right)\frac{f'(x)-f'(a+b-x)}{2}\\+\frac{f'(b)-f'(a)}{b-a}\left[\frac{1}{2}\left(x-\frac{3a+b}{4}\right)^2+\frac{(b-a)^2}{96}\right]-\frac{1}{b-
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![Ctex这个公式怎么换行.换三行\begin{equation}\left|\frac{f(x)+f(a+b-x)}{2}-\left(x-\frac{3a+b}{4}\right)\frac{f'(x)-f'(a+b-x)}{2}\\+\frac{f'(b)-f'(a)}{b-a}\left[\frac{1}{2}\left(x-\frac{3a+b}{4}\right)^2+\frac{(b-a)^2}{96}\right]-\frac{1}{b-](/uploads/image/z/8772040-64-0.jpg?t=Ctex%E8%BF%99%E4%B8%AA%E5%85%AC%E5%BC%8F%E6%80%8E%E4%B9%88%E6%8D%A2%E8%A1%8C.%E6%8D%A2%E4%B8%89%E8%A1%8C%5Cbegin%7Bequation%7D%5Cleft%7C%5Cfrac%7Bf%28x%29%2Bf%28a%2Bb-x%29%7D%7B2%7D-%5Cleft%28x-%5Cfrac%7B3a%2Bb%7D%7B4%7D%5Cright%29%5Cfrac%7Bf%27%28x%29-f%27%28a%2Bb-x%29%7D%7B2%7D%5C%5C%2B%5Cfrac%7Bf%27%28b%29-f%27%28a%29%7D%7Bb-a%7D%5Cleft%5B%5Cfrac%7B1%7D%7B2%7D%5Cleft%28x-%5Cfrac%7B3a%2Bb%7D%7B4%7D%5Cright%29%5E2%2B%5Cfrac%7B%28b-a%29%5E2%7D%7B96%7D%5Cright%5D-%5Cfrac%7B1%7D%7Bb-)
Ctex这个公式怎么换行.换三行\begin{equation}\left|\frac{f(x)+f(a+b-x)}{2}-\left(x-\frac{3a+b}{4}\right)\frac{f'(x)-f'(a+b-x)}{2}\\+\frac{f'(b)-f'(a)}{b-a}\left[\frac{1}{2}\left(x-\frac{3a+b}{4}\right)^2+\frac{(b-a)^2}{96}\right]-\frac{1}{b-
Ctex这个公式怎么换行.换三行
\begin{equation}
\left|\frac{f(x)+f(a+b-x)}{2}-\left(x-\frac{3a+b}{4}\right)\frac{f'(x)-f'(a+b-x)}{2}\\
+\frac{f'(b)-f'(a)}{b-a}\left[\frac{1}{2}\left(x-\frac{3a+b}{4}\right)^2+\frac{(b-a)^2}{96}\right]
-\frac{1}{b-a}\int_{a}^{b}f(t)dt\right|\\
\leq\frac{1}{8}(\Gamma-\gamma)\left[\frac{b-a}{4}+\left|x-\frac{3a+b}{4}\right|\right]^2.
\end{equation}
Ctex这个公式怎么换行.换三行\begin{equation}\left|\frac{f(x)+f(a+b-x)}{2}-\left(x-\frac{3a+b}{4}\right)\frac{f'(x)-f'(a+b-x)}{2}\\+\frac{f'(b)-f'(a)}{b-a}\left[\frac{1}{2}\left(x-\frac{3a+b}{4}\right)^2+\frac{(b-a)^2}{96}\right]-\frac{1}{b-
按回车即可,楼主糊涂了吧