等差数列{an}的前n项和为Sn,公差为d,已知(a8+1)^3+2013(a8+1)=1,(a2006+1)^3+2013(a2006+1)=-1则求d与0大小关系,S2013=?
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![等差数列{an}的前n项和为Sn,公差为d,已知(a8+1)^3+2013(a8+1)=1,(a2006+1)^3+2013(a2006+1)=-1则求d与0大小关系,S2013=?](/uploads/image/z/8783362-10-2.jpg?t=%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E5%85%AC%E5%B7%AE%E4%B8%BAd%2C%E5%B7%B2%E7%9F%A5%28a8%2B1%29%5E3%2B2013%28a8%2B1%29%3D1%2C%EF%BC%88a2006%2B1%EF%BC%89%5E3%2B2013%EF%BC%88a2006%2B1%EF%BC%89%3D-1%E5%88%99%E6%B1%82d%E4%B8%8E0%E5%A4%A7%E5%B0%8F%E5%85%B3%E7%B3%BB%2CS2013%3D%3F)
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等差数列{an}的前n项和为Sn,公差为d,已知(a8+1)^3+2013(a8+1)=1,(a2006+1)^3+2013(a2006+1)=-1则求d与0大小关系,S2013=?
等差数列{an}的前n项和为Sn,公差为d,已知(a8+1)^3+2013(a8+1)=1,(a2006+1)^3+2013(a2006+1)=-1
则求d与0大小关系,S2013=?
等差数列{an}的前n项和为Sn,公差为d,已知(a8+1)^3+2013(a8+1)=1,(a2006+1)^3+2013(a2006+1)=-1则求d与0大小关系,S2013=?
等差数列{an}的前n项和为Sn,公差为d,已知(a8+1)^3+2013(a8+1)=1,(a2006+1)^3+2013(a2006+1)=-1
由(a8+1)^3+2013(a8+1)=1得a8+1>0
由(a2006+1)^3+2013(a2006+1)=-1得a2006+10
所以d0
所以a8+a2006+2=0
所以S2013=(a1+a2013)*2013/2=(a8+a2006)*2013/2=(-2)*2013/2=-2013
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