已知存在实数a,b使等式2²+4²+6²+...+(2n)²=n(n+1)(an+b)对任意的正整数n都成立,则a,b=
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![已知存在实数a,b使等式2²+4²+6²+...+(2n)²=n(n+1)(an+b)对任意的正整数n都成立,则a,b=](/uploads/image/z/8791974-54-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AD%98%E5%9C%A8%E5%AE%9E%E6%95%B0a%2Cb%E4%BD%BF%E7%AD%89%E5%BC%8F2%26%23178%3B%2B4%26%23178%3B%2B6%26%23178%3B%2B...%2B%282n%29%26%23178%3B%3Dn%28n%2B1%29%28an%2Bb%29%E5%AF%B9%E4%BB%BB%E6%84%8F%E7%9A%84%E6%AD%A3%E6%95%B4%E6%95%B0n%E9%83%BD%E6%88%90%E7%AB%8B%2C%E5%88%99a%2Cb%3D)
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已知存在实数a,b使等式2²+4²+6²+...+(2n)²=n(n+1)(an+b)对任意的正整数n都成立,则a,b=
已知存在实数a,b使等式2²+4²+6²+...+(2n)²=n(n+1)(an+b)
对任意的正整数n都成立,则a,b=
已知存在实数a,b使等式2²+4²+6²+...+(2n)²=n(n+1)(an+b)对任意的正整数n都成立,则a,b=
2^2+4^2+6^2+.+(2n)^2
=4(1+2^2+3^2+...+n^2)
=4*1/6*n*(n+1)*(2n+1)
=2/3 *n*(n+1)*(2n+1)
所以2/3*(2n+1)=an+b
a=4/3 b=2/3