求一元二次方程x²-x-1=0的根x1,x2(1)x1²+x2² (2)x1分之1 + x2分之1(3)(x1-x2)² (4)(x1+1)(x2+1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/03 12:44:35
![求一元二次方程x²-x-1=0的根x1,x2(1)x1²+x2² (2)x1分之1 + x2分之1(3)(x1-x2)² (4)(x1+1)(x2+1)](/uploads/image/z/8793069-69-9.jpg?t=%E6%B1%82%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%26%23178%3B-x-1%3D0%E7%9A%84%E6%A0%B9x1%2Cx2%EF%BC%881%EF%BC%89x1%26%23178%3B%2Bx2%26%23178%3B+%EF%BC%882%EF%BC%89x1%E5%88%86%E4%B9%8B1+%2B+x2%E5%88%86%E4%B9%8B1%EF%BC%883%EF%BC%89%EF%BC%88x1-x2%EF%BC%89%26%23178%3B+%EF%BC%884%EF%BC%89%28x1%2B1%29%28x2%2B1%29)
x͑R0_s21>i%[>%5=2|hd`H"U(hr8J^?``RpH*&ϋ߇_//Ζ?7HƯC7?,-lZr{uW'Z=
<'F>xtӨf!\8y0E.-0-qkzH㟸zP5Iˉ9.gDBwPMݰDB{PSa?~̓Q"o+-hjMQ]ɽI)ik1(Po]>}-lVBH*i=R4Gz)Tl7
5FrJ$Q\cULK
QS\LK!'12j1ѻʡdkD,\8*0eFh9u|MԎawՄ
求一元二次方程x²-x-1=0的根x1,x2(1)x1²+x2² (2)x1分之1 + x2分之1(3)(x1-x2)² (4)(x1+1)(x2+1)
求一元二次方程x²-x-1=0的根x1,x2
(1)x1²+x2² (2)x1分之1 + x2分之1
(3)(x1-x2)² (4)(x1+1)(x2+1)
求一元二次方程x²-x-1=0的根x1,x2(1)x1²+x2² (2)x1分之1 + x2分之1(3)(x1-x2)² (4)(x1+1)(x2+1)
一元二次方程x²-x-1=0的根x1,x2
x1+x2=1,x1x2=-1
x1²+x2² =(x1+x2)²-2x1x2=-+2=3
x1分之1 + x2分之1=(x1+x2)/x1x2=1/(-1)=-1
(x1-x2)²=(x1+x2)²-4x1x2=1+4=5
(x1+1)(x2+1)=x1x2+x1+x2+1=1-1+1=1