作业帮1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)化简怎么算?
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1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)化简怎么算?
1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)化简怎么算?
1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)化简怎么算?
原式等于1/x-1/(x+3)
首先1/X（1+X）=1/X-1/1+X（可以通分验证）
之后每一项都这样打开 如1/(x+1)(x+2）=1/(x+1)-1/(x+2）
中间的全部消掉..得到答案
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分解因式----（X*X-X)(X*X-X-2)+1
】x(x+1)+x^2(x-1)
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