作业帮mathematica 解方程Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) - cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]我这样写对吗？但用/.带进去算输出不是零是什么问题？
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/11 23:06:30
![mathematica 解方程Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) - cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]我这样写对吗？但用/.带进去算输出不是零是什么问题？](/uploads/image/z/8794438-70-8.jpg?t=mathematica+%E8%A7%A3%E6%96%B9%E7%A8%8BSolve%5Bcos+%286%5E%281%2F2%29%2F3%2A%28t+%2B+t3%2F2%29%29%2Asin+%286%5E%281%2F2%29%2F3%2At3%2F2%29+-+cos+%286%5E%281%2F2%29%2F3%2A%28t+%2B+t2+%2B+t3+%2B+t1%2F2%29%29%2Asin+%286%5E%281%2F2%29%2F3%2At1%2F2%29+%3D%3D+0%2Ct%5D%E6%88%91%E8%BF%99%E6%A0%B7%E5%86%99%E5%AF%B9%E5%90%97%EF%BC%9F%E4%BD%86%E7%94%A8%2F.%E5%B8%A6%E8%BF%9B%E5%8E%BB%E7%AE%97%E8%BE%93%E5%87%BA%E4%B8%8D%E6%98%AF%E9%9B%B6%E6%98%AF%E4%BB%80%E4%B9%88%E9%97%AE%E9%A2%98%EF%BC%9F)
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mathematica 解方程Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) - cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]我这样写对吗？但用/.带进去算输出不是零是什么问题？
mathematica 解方程
Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) -
cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]
我这样写对吗？但用/.带进去算输出不是零是什么问题？
mathematica 解方程Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) - cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]我这样写对吗？但用/.带进去算输出不是零是什么问题？
首先,不符合基本语法.可以写成这样的形式：
Solve[Cos@(6^(1/2)/3*(t + t3/2))*Sin@ (6^(1/2)/3*t3/2) -
Cos@ (6^(1/2)/3*(t + t2 + t3 + t1/2))*Sin@(6^(1/2)/3*t1/2) == 0, t]
然后求解我就没法帮了,里面的t1,t2,t3是你之前的赋值吧?欢迎追问