已知sin(π/6-α)=a,则cos(2π/3-α)=
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/19 01:39:20
x){}K347ۨicfr~P,dTOR;EX.PD<;6`P=`tMѝq5mt!
t!@b${d{zPP ։{
已知sin(π/6-α)=a,则cos(2π/3-α)=
已知sin(π/6-α)=a,则cos(2π/3-α)=
已知sin(π/6-α)=a,则cos(2π/3-α)=
cos(2π/3-α)
=cos[(π/6-α)+π/2]
=-sin(π/6-α)
=-a
sin(π/6-a)=cos[π/2-(π/6-a)]=cos(π/3+a)= -cos[π-(π/3+a)]=-cos(2π/3-a)=a
所以,cos(2π/3-a)=-a
已知2sin(a/2)=cos(a/2),则sin(a+π/6)=
已知sin(π/6-α)=a,则cos(2π/3-α)=
已知cos(π/6-a)=1/3,则cos(5π/6+a)sin(2π/3-a=?
已知cos^2A+cosA=1,则sin^6A+sin^2A=?
设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π+α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2(-sinα)(-cosα)+cosα/[1+sin²
已知sina+sin^2a=1,则cos^2a+cos^6a+cos^8a=
已知 sin a-cos a=1/2,则 sin^3 a-cos^3 a
已知sin a=2cos a 计算⑴(sinα+2cosα)/(5cosα-sinα) ⑵tan(α+π/4)
已知cos(a-π/6)=-1/3则sin(2π/3-a)=?
已知sin(π/3 -a)=1/4 则cos(7/6π+a)=
已知sin(π/3 -a)=1/2,则cos(π/6 +a)=?
已知cos(π/6-a)=2/3 则sin(a-2π/3)=?
已知tana=2,则[sin(π/2+a)-cos(π-a)]/[sin(π/2-a)-sin(π-a)]=?
已知sin(π/6-a)=根号3/3,则 cos(4π/3+a)
已知sin(π/6+a)=1/3则cos(π/3-a)的值
已知sin(a-π/3)=1/3,则cos(π/6+a)的值为?
已知sin(6/π+a)=1/3,则cos(π/3-a)的值是
已知sin(a-π/3)=1/3,则cos(a+π/6)等于