lim(n→oo)(1/2+1/2^2+……+1/2^n)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 17:09:20
x){6)?_SPH㌴5,"0'O&H(uv6ělƾ-۞O|mSMcY-66=u=O?ٽ/'ua7,e d+hE*,ˋU2uA
Xe';;Yb[]}Ϧ/xr;ӷ=mU48$0ig_Μaϓm@
lim(n→oo)(1/2+1/2^2+……+1/2^n)
lim(n→oo)(1/2+1/2^2+……+1/2^n)
lim(n→oo)(1/2+1/2^2+……+1/2^n)
显然由等比数列的求和公式可以知道,
1/2+1/2^2+……+1/2^n
= 1/2 *[1- (1/2)^n] / (1-1/2)
= 1- (1/2)^n
那么在n趋于无穷的时候,(1/2)^n趋于0
所以
原极限值为 1
lim(n→oo)(1/2+1/2^2+……+1/2^n)
lim 4n^2+2/3n^2+1 (n→oo)lim (√(n+1)- √(n)) (n→oo)lim √x+△x - √x / △x (△x→0)lim 1+2+…+n / n^2 (n→oo)
lim(2/2*3*4+2/3*4*5+...2/(n+1)(n+2)(n+3)) n→oo
极限lim(n->oo) n[ln(2+1/n)-ln2] 怎样算?貌似要用导数的?.极限lim(n->oo) n[ln(2+1/n)-ln2]怎样算?貌似要用导数的?.
lim x(x+2)/x^2 (x→oo)lim 1/sin(x-2) (x→2)
化简并求值:(m+n)^2+(m+n)(m-3n)其中m=√2,n=1o(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(╯□╰)oo(
lim(n→oo)(3^n/n)^1/n的值是什么
lim(n→oo)√n(√n+1-√n)
lim (1+1/2+1/4+…+1/2^n) / (1+1/3+1/9+…+1/3^n) (n→oo)lim (x^n)-1/x-1 (x→1)lim ((1/x+1)-(3/x^3 +1)) (x→-1)
用数列极限的定义证明lim n^(1/n)=1lim n^(1/n)=1 (n→+oo)
求lim n→∞ (1+2/n)^n+3
lim(n→∞)[1-(2n/n+3)]
lim(n→∞)(2n-1/n+3)
lim(1-1/n)^(n^2)=?
lim(1-1/n^2)^n=?
lim(n→∞) ((2n!/n!*n)^1/n的极限用定积分求是lim(n→∞) 1/n(2n!/n!)^1/n 不好意思
lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞
lim(x→0)(n/(n+1)^2)能用洛必达求吗?