Brandon and Shanda walk to grandma's house at a rate of 4 mph.they ride their bicycles back home at a rate of 8 mph over the same route that they walked .it takes one hour longer to walk than ride .how long did it take them to walk to Grandma's?
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Brandon and Shanda walk to grandma's house at a rate of 4 mph.they ride their bicycles back home at a rate of 8 mph over the same route that they walked .it takes one hour longer to walk than ride .how long did it take them to walk to Grandma's?
Brandon and Shanda walk to grandma's house at a rate of 4 mph.they ride their bicycles back home at a rate of 8 mph over the same route that they walked .it takes one hour longer to walk than ride .how long did it take them to walk to Grandma's?
Brandon and Shanda walk to grandma's house at a rate of 4 mph.they ride their bicycles back home at a rate of 8 mph over the same route that they walked .it takes one hour longer to walk than ride .how long did it take them to walk to Grandma's?
Let t be the time for walklng and s be the distance.
Then 4t = 8(t-1) ; 4t = 8t -8; t = 2 hours; Therefore,s = 4t = 8 miles
ANS: assume x hours for walking then x-1 hours for riding x*4= 8*(x-1) x= 2
翻译:
布兰登和盛大走到祖母家的速度在每小时4英里的速度。他们骑自行车回家的速度在每小时8英里,他们走相同的路线。它需要一个小时,再走路比骑。他们花了多少时间去奶奶家?
Let "t" be the time for walklng and "s" be the distance.
Then 4t = 8(t-1) ;
4t = 8t -8;
t = ...
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翻译:
布兰登和盛大走到祖母家的速度在每小时4英里的速度。他们骑自行车回家的速度在每小时8英里,他们走相同的路线。它需要一个小时,再走路比骑。他们花了多少时间去奶奶家?
Let "t" be the time for walklng and "s" be the distance.
Then 4t = 8(t-1) ;
4t = 8t -8;
t = 2 hours;
Therefore, s = 4t = 8 miles
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