sin(π-α)-cos(π+α)=根号2/4(0
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/03 19:03:01
x)+8ߠ{nnr~1
d>[iv#}
"}"Tk
~O=sB6* r092蹍`Cu6<ٽi{mP7X1hqqF
O{7j H#?%OMھH|~qAb
sin(π-α)-cos(π+α)=根号2/4(0
sin(π-α)-cos(π+α)=根号2/4(0
sin(π-α)-cos(π+α)=根号2/4(0
因为 sin(π-α)=sinα cos(π+α)=-cosα
所以原式=sinα+ cosα=根号二/4
则(sinα+ cosα)^2=1/8 即1+2sinαcosα=1/8
所以2sinαcosα=-7/8 由此得出2/π