8(3^2+1)(3^4+1)(3^8+1)...(3^32+1)+1已知:a^2-3a-1=0,a^2+1/a^2=?
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8(3^2+1)(3^4+1)(3^8+1)...(3^32+1)+1已知:a^2-3a-1=0,a^2+1/a^2=?
8(3^2+1)(3^4+1)(3^8+1)...(3^32+1)+1
已知:a^2-3a-1=0,a^2+1/a^2=?
8(3^2+1)(3^4+1)(3^8+1)...(3^32+1)+1已知:a^2-3a-1=0,a^2+1/a^2=?
8(3^2+1)(3^4+1)(3^8+1)...(3^32+1)+1
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)...(3^32+1)+1
=(3^4-1)(3^4+1)(3^8+1)...(3^32+1)+1
=(3^8-1)(3^8+1)...(3^32+1)+1
=.
=(3^32-1)(3^32+1)+1
=(3^64-1)+1
=3^64
已知:a^2-3a-1=0,a^2+1/a^2=?
由a^2-3a-1=0知a≠0
所以a-1/a=3
两边平方得:
a^2-2+1/a^2=9
所以
a^2+1/a^2=9+2=11
第一题:乘以(3^2-1),连续用平方差公式,再除回来
原式=8(3^64-1)/(3^2-1) +1 =3^64
第二题:a-3-1/a=0
a-1/a=3
两边平方
a^2 - 2 + 1/a^2 =9
故答案为11
(-4/3)*(-8+3/2-3/1)
1+2+3+4+3+315-8
计算:8(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
计算:(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
简便计算(3+1)(3^2+1)(3^4+1)(3^8+1)+(3^16+1)
(3+1)(3^2+1)(3^4+1)(3^8+1)-3^16/2
1:8 2:9 1:9 3:4 1:3 ...
1+2+3 2+4+8
简便运算2*(1+3)(1+3^2)(1+3^4)(1+3^8)+1
计算:2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1
1/1*2*3+1/2*3*4+1/3*4*5+.+1/8*9*10
1/8+2/5x 3/4
11/8-(2/3-1/4)
1+2+3+4、、、+8+9=
5/8-3/4+1/2
1、2、3、4、5、7、8