斐波那契额数列# include int main(){int i = 1,j = 2,n,k = 0; printf ("请输入你要求的项数\n");scanf (" %d",&n); if (n==1)printf("您要求的和是1\n");else if (n==2)printf("您要求的和是2\n");else if(n>=3)for (;3

斐波那契额数列# include int main(){int i = 1,j = 2,n,k = 0; printf ("请输入你要求的项数\n");scanf (" %d",&n); if (n==1)printf("您要求的和是1\n");else if (n==2)printf("您要求的和是2\n");else if(n>=3)for (;3
斐波那契额数列
# include
int main()
{
int i = 1,j = 2,n,k = 0;
printf ("请输入你要求的项数\n");
scanf (" %d",&n);
if (n==1)
printf("您要求的和是1\n");
else if (n==2)
printf("您要求的和是2\n");
else if(n>=3)
for (;3

斐波那契额数列# include int main(){int i = 1,j = 2,n,k = 0; printf ("请输入你要求的项数\n");scanf (" %d",&n); if (n==1)printf("您要求的和是1\n");else if (n==2)printf("您要求的和是2\n");else if(n>=3)for (;3
你算的不是那一项的大小吗 怎么输出说要的“和”?
如果是要指定项的大小 那你就只要把printf("您要和是 %d\n",j);
放到for循环外就可以了