数列An满足a1=二分之一,A(n-1)+1=2An,(大于等于2,n属于N),求An通项公式(2)若数n满足 2b1+2^2b2+...+2^nbn+n2^n,求bn的通项公式 (3)令cn=2anbn.(n属于n+)求数列cn的前n项和Tn
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![数列An满足a1=二分之一,A(n-1)+1=2An,(大于等于2,n属于N),求An通项公式(2)若数n满足 2b1+2^2b2+...+2^nbn+n2^n,求bn的通项公式 (3)令cn=2anbn.(n属于n+)求数列cn的前n项和Tn](/uploads/image/z/8824379-59-9.jpg?t=%E6%95%B0%E5%88%97An%E6%BB%A1%E8%B6%B3a1%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80%2CA%28n-1%29%2B1%3D2An%2C%28%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E2%2Cn%E5%B1%9E%E4%BA%8EN%29%2C%E6%B1%82An%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%882%EF%BC%89%E8%8B%A5%E6%95%B0n%E6%BB%A1%E8%B6%B3+2b1%2B2%5E2b2%2B...%2B2%5Enbn%2Bn2%5En%2C%E6%B1%82bn%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F+%EF%BC%883%EF%BC%89%E4%BB%A4cn%3D2anbn.%EF%BC%88n%E5%B1%9E%E4%BA%8En%2B%EF%BC%89%E6%B1%82%E6%95%B0%E5%88%97cn%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CTn)
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