已知数列{an},a1=1,a(k+1)=(2^k) * (ak),(k≥1)1.若bn=log2(an)/(4^n),求数列{bn}的最小项的值2.数列{cn}的前n项和为bn,求数列{绝对值cn}前项的和 Sn
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![已知数列{an},a1=1,a(k+1)=(2^k) * (ak),(k≥1)1.若bn=log2(an)/(4^n),求数列{bn}的最小项的值2.数列{cn}的前n项和为bn,求数列{绝对值cn}前项的和 Sn](/uploads/image/z/8828983-55-3.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%2Ca1%3D1%2Ca%28k%2B1%29%3D%282%5Ek%29+%2A+%28ak%29%2C%28k%E2%89%A51%291.%E8%8B%A5bn%3Dlog2%28an%29%2F%284%5En%29%2C%E6%B1%82%E6%95%B0%E5%88%97%EF%BD%9Bbn%EF%BD%9D%E7%9A%84%E6%9C%80%E5%B0%8F%E9%A1%B9%E7%9A%84%E5%80%BC2.%E6%95%B0%E5%88%97%EF%BD%9Bcn%EF%BD%9D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BAbn%2C%E6%B1%82%E6%95%B0%E5%88%97%EF%BD%9B%E7%BB%9D%E5%AF%B9%E5%80%BCcn%EF%BD%9D%E5%89%8D%E9%A1%B9%E7%9A%84%E5%92%8C+Sn)
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