Please help me.做以上题目.
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Please help me.做以上题目.
Please help me.做以上题目.
Please help me.做以上题目.
2;一般方程为2x-y+3=0
3;方程可写为3x+y=-3故在y轴上的截距为3
4;直线ax+by+c=0的方向向量为(b,-a)此题中为(-2,-3)法向量为(a,b)此题中为(3,-2)
5;斜率为-a/b,故为-3
画图暂时不方便传,不好意思~
Please help me.做以上题目.
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