(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2
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(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2
(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③
(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2
(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2
(1)①×2-②:
3y+5z=21 ④
①×3-③:
5y+7z=31 ⑤
④×5-⑤×3:
z=3,代入前面④ y=2,x=1.
(2)①不对,应该是:
(x-3)/2+3≥x+1
x-3+6≥2x+2
x≤1
② 1-3x+3<8-x,
3x-x>1+3-8
2x>-4,
∴x>-2.
-2<x≤1
(3)①x-5>1+2x
x<-6
②3x+2<4x
4x-3x>2
x>2
没有公共部分.
(4)(√0.01+³√0.001)×√144
=0.1×0.1×12
=0.12
(5)|√2-√5|-|√5+√2|
=√5-√2-(√5+√2)
=√5-√2-√5-√2
=-2√2.
x+y+z=6 x+2y+3z=14 y+1=z
(1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1.
已知xyz≥0,x+y+z=1,化简x(2y-z)/(1+x+3y)+y(2z-x) /(1+y+3z) +z(2x-y)/(1+z+3x)
3x+2y+z=14 x+y+2z+-3 2x+3y-z=1
[3x+2y+z=14,x+y+z=10,2x+3y-z=1]
3x+2y+z=14 { x+y+z=10 2x+3y-z=1
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
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解三元一次方程组.速回.(1)X+Y+Z=25 X-Y=1 2X+Y-Z=18(2)X-Y-Z=0 X+Y-3Z=4 2X+3Y-5Z=14(3) X-2Y=-9 Y-Z=3 2Z+x=47(4)3X-y+z=4 2X+3Y-Z=12 X+Y+z=-28(5)4X+9Y=13 3y-2Z=-1 7X+5Z=17速回 我会奖励积分
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值