如图:过平行四边形ABCD的顶点C作射线CP分别交BD、AD于E、F,交BA的延长线与G(1)求证:CE²=EF·EG(2)若GF=3,CE=2,求EF的长.急
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![如图:过平行四边形ABCD的顶点C作射线CP分别交BD、AD于E、F,交BA的延长线与G(1)求证:CE²=EF·EG(2)若GF=3,CE=2,求EF的长.急](/uploads/image/z/8837798-14-8.jpg?t=%E5%A6%82%E5%9B%BE%EF%BC%9A%E8%BF%87%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E7%9A%84%E9%A1%B6%E7%82%B9C%E4%BD%9C%E5%B0%84%E7%BA%BFCP%E5%88%86%E5%88%AB%E4%BA%A4BD%E3%80%81AD%E4%BA%8EE%E3%80%81F%2C%E4%BA%A4BA%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8EG%281%29%E6%B1%82%E8%AF%81%EF%BC%9ACE%26%23178%3B%3DEF%C2%B7EG%282%29%E8%8B%A5GF%3D3%2CCE%3D2%2C%E6%B1%82EF%E7%9A%84%E9%95%BF.%E6%80%A5)
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