f(x)=x²-x-1,则f(x+1)=
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f(x)=x²-x-1,则f(x+1)=
f(x)=x²-x-1,则f(x+1)=
f(x)=x²-x-1,则f(x+1)=
答:
f(x)=x²-x-1
f(x+1)=(x+1)²-(x+1)-1
=x²+2x+1-x-1-1
=x²+x-1
所以:
f(x+1)=x²+x-1
f(x)=x²-x-1, 则f(x+1)= (x+1)²-(x+1)-1 =x²+2x+1-x-1-1 =x²+x-1