f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间
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f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间
f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间
f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间
函数f(x)=根号2*sin(2x+π/4)单调增区间为:
2kπ-π/2≤2x+π/4≤2kπ+π/2
化简得:kπ-3π/8≤x≤kπ+π/8
因为x属于【-π/2,π/2】
所以k=0,-3π/8≤x≤π/8
即函数单调增区间为[-3π/8,π/8]
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